# SOLUTION: Hello I am not sure how to go about this. If the sides of a square are decreased by 3cm, the area is decreased by 81cm^2. What were the dimensions of the original square. I am thin

Algebra ->  Algebra  -> Polynomials-and-rational-expressions -> SOLUTION: Hello I am not sure how to go about this. If the sides of a square are decreased by 3cm, the area is decreased by 81cm^2. What were the dimensions of the original square. I am thin      Log On

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 Question 92180: Hello I am not sure how to go about this. If the sides of a square are decreased by 3cm, the area is decreased by 81cm^2. What were the dimensions of the original square. I am thinking (x-3)^2=a-81cm^3, but where do I go from here?Answer by Earlsdon(6287)   (Show Source): You can put this solution on YOUR website!Well, your initial idea is right on! Where A = original area and x = the original length of the side of the square. The next step is to recall that , that is; the original area (A) is equal to the original sides squared , so substitute the A with in the first equation then solve for x. Expand the left side. Subtract from both sides. Subtract 9 from both sides. Finally, divide both sides by -6. cm. Check: