SOLUTION: How to find the leading coefficient of this polynomial: H(x) = (2x+6)(x-3)^2(x+1)^3 x-int: (-3,0),(3,0),(-1,0) y-int: (0,54) I know the degree is 6 by adding the exponent

Question 916912: How to find the leading coefficient of this polynomial:
H(x) = (2x+6)(x-3)^2(x+1)^3
x-int: (-3,0),(3,0),(-1,0)
y-int: (0,54)
I know the degree is 6 by adding the exponents, right?
But how do I find the leading coefficient?
Please help
Thank you
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
One term of will occur when you multiply to get the product; no other terms of will occur, so you can find this leading term separately from the other terms containing x.

will be the term with this degree of 6.
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