SOLUTION: I need to see the steps to solve 1-x^-1-20x^-2=0

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Question 913834: I need to see the steps to solve 1-x^-1-20x^-2=0
Found 3 solutions by josgarithmetic, MathLover1, lwsshak3:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
lowest common denominator is , so best suggestion is multiply the left and right members by . You will then solve a quadratic equation. Do the first two steps, simplify, and you should understand a fairly predictable solution path. The only reason you might not know how to start is forgotten what negative exponent means.

You are starting with .
Multiply left and right by .........
......in fact when you do this you should find that the quadratic is factorable.

Answer by MathLover1(20849)   (Show Source): You can put this solution on YOUR website!
















solutions:





or






Answer by lwsshak3(11628)   (Show Source): You can put this solution on YOUR website!
solve
let u=x^-1
u^2=x^-2
1-u-20u^2=0
20u^2+u-1=0
(4u+1)(5u-1)=0
u=-1/4=x^-1
-1/4=(1/x)
x=-4
or
u=1/5=x^-1
1/5=1/x
x=5
Check:
f(-4)=1-x^-1-20x^-2
f(-4)=1-1/x-20/x^2
f(-4)=1+1/4-20/16=5/4-5/4=0
f(5)=1-1/5-20/25=4/5-4/5=0
Both zeros check ok

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