SOLUTION: 1)find three consecutive positive even integers such that the product of the first and third integer is equal to one less then four times the second integer 2)the lenght of a

Question 901736: 1)find three consecutive positive even integers such that the product of the first and third integer is equal to one less then four times the second integer

2)the lenght of a rectangle is 2 more than twice its width. the area of the rectangle is 40 ft squared. find the lenght and width .

3)find four consecutive positive integers such the 3 times the second interger is 12 more the 2 times the fourth integer

5)the area of a square, expressed in square centimeters is 96 grater then its perimeter expressed in centimeters, what is the length of the side of the square
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
2) A = Lw = (2w+2)w = 40ft^2
Solve for w
2w^2 + 2w - 40 = 0
w^2 + w - 20 = (w+5)(w-4), w = 4ft(using Positive Solution) and L = 10ft
5) s^2 = 4s+96
solve for s
s^2 - 4x - 96 = (s+8)(s-12), s = 12 (using Positive Solution)
and 144 = 48+96
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