SOLUTION: solve
(x-5)^2=7
A)-5+(minus underneath the plus) square root of 7
B) 5+(minus underneath the plus) square root of 7
C) +(minus underneath the plus) square root of 54
D) +(
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Question 90159: solve
(x-5)^2=7
A)-5+(minus underneath the plus) square root of 7
B) 5+(minus underneath the plus) square root of 7
C) +(minus underneath the plus) square root of 54
D) +(minus underneath the plus)54
Answer by tutorcecilia(2152) (Show Source): You can put this solution on YOUR website!
= 7 [take the square root of both sides of the equation]
=
.
x-5 = [add (5) to both sides of the equation]
x = 5
Answer: B
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