SOLUTION: How would I factor this to leave a all by itself? m2g -m2a = m1a + m1g

Question 901145: How would I factor this to leave a all by itself?
m2g -m2a = m1a + m1g
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
How would I factor this to leave a all by itself?
m2g -m2a = m1a + m1g
--------
If you mean solve for a:
m2g -m2a = m1a + m1g
Get all terms with a on one side
m2g -m1g = m1a - m2a
m2g -m1g = a*(m1 - m2)
(m2g -m1g)/(m1 - m2) = a
a = (m2g -m1g)/(m1 - m2) = g(m2 - m1)/(m1 - m2)
a = -g

RELATED QUESTIONS
How would I factor to leave a on one... (answered by richwmiller)

Hi I would like to ask you how to get Y by itself in this system of equation 4x -1y = (answered by MathLover1)

P=sigma*A*e*T^4 solve for T how would I simplify this having T by itself? (answered by Fombitz)

How would I solve to leave (a) on one... (answered by richwmiller)

If I have 6 objects labeled A-F and I need to know how many different combinations that... (answered by sudhanshu_kmr)

When a number is decreased by 30 of itself ,the result is 28 . What is the number ? I... (answered by Fombitz)

How do I graph to get "y" by... (answered by MathLover1)

Graph. x + y < 1 How would i graph this? do i need to solve it at all or leave it... (answered by Alan3354,vleith)

Graph: y ≥ 2x + 1 How would i graph this? do i need to solve it at all or... (answered by Alan3354)