SOLUTION: solve by using the quadratic formula 4x^2-3x+3=0
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Question 89963
:
solve by using the quadratic formula
4x^2-3x+3=0
Answer by
checkley75(3666)
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4x^2-3x+3=0
x=(3+-sqrt[-3^2-4*4*3])/2*4
x=(3+-sqrt[9-48])/8
x=(3+-sqrt-39)/8
x=(3+-6.245i)/8
x=(3+6.245i)/8
x=3/8+6.245i/8
x=3/8+.78i answer.
x=(3-6.245i)/8
x=3/8-6.245i/8
x=3/8-.78i answer.