SOLUTION: How do I solve for "x" in "-3x^2+2=29"?
I know the first thing is to subtract "29" from both sides, so:
"-3x^2+27=0"
From there I am not certain what to do.
Algebra.Com
Question 896832: How do I solve for "x" in "-3x^2+2=29"?
I know the first thing is to subtract "29" from both sides, so:
"-3x^2+27=0"
From there I am not certain what to do.
Found 2 solutions by josgarithmetic, Alan3354:
Answer by josgarithmetic(39623) (Show Source): You can put this solution on YOUR website!
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The 0 in the answer is only included for rendering on the page and is not really needed.
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means that or .
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
How do I solve for "x" in "-3x^2+2=29"?
I know the first thing is to subtract "29" from both sides, so:
"-3x^2+27=0"
-------------
-3x^2+2=29
Or, subtract 2
-3x^2 = 27
Divide by -3
x^2 = -9
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