SOLUTION: solve by completing the square
x^2-6x-3=0
Algebra.Com
Question 89338: solve by completing the square
x^2-6x-3=0
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
solve by completing the square
x^2-6x-3=0
---------
x^2-6x + (6/2)^2 = 3+(6/2)^2
x^2-6x+9 = 12
Factor the left side to get:
(x-3)^2 = 12
Take the square root of both sides to get:
(x-3) = 2sqrt3 or (x-3) = -2sqrt3
Solve for x:
x= 3+2sqrt3 or x= 3-2sqrt3
===============
Cheers,
Stan H.
RELATED QUESTIONS
Solve by completing the square... (answered by nyc_function)
Solve by completing the square.
x^2 + 6x + 2 =... (answered by Earlsdon)
Solve by completing the square:
x^2 + 6x +1 =... (answered by elima)
Solve by completing the square:
x^2 + 6x + 1 = 0
(answered by psbhowmick,jim_thompson5910)
Solve by completing the square:
x^2 + 6x + 1 = 0
(answered by nerdybill)
Solve by completing the square:
x^2 + 6x + 4 = 0
(answered by jim_thompson5910)
Solve by completing the square:... (answered by vleith)
Solve by completing the square.... (answered by erica65404,josmiceli)
Solve by completing the square. 2x^2 – 6x – 3 =... (answered by ankor@dixie-net.com,jim_thompson5910)