SOLUTION: Use the Binomial Theorem to write out and simplify the first four terms in the expansion of the (2a+3b)^7.
Simplifying a term means to remove all parentheses and evaluate binom
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Question 89161This question is from textbook INTERMEDIATE ALGEBRA
: Use the Binomial Theorem to write out and simplify the first four terms in the expansion of the (2a+3b)^7.
Simplifying a term means to remove all parentheses and evaluate binomial coefficients. For example, the 3rd term of (2a+3b)^7 is given below in simplified form.
Third term = (7 over 2)(2a)^5(3b)^2=21*2^5a^5*2^2b^2= 6048a^5b^2
This question is from textbook INTERMEDIATE ALGEBRA
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Use the Binomial Theorem to write out and simplify the first four terms in the expansion of the (2a+3b)^7.
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7C7(2a)^7 + 7C6(2a)^6(3b) + 7C5(2a)^5(3b)^2 + 7C4(2a)^4(3b)^3
= 128a^7 + 7(64a^6)(3b) + 21(32a^5)(9b^2) + 35(16a^4)(27b^3)
= 128a^7 + 1344a^6b + 6048a^5b^2 + 15120a^4b^3
============
Cheers,
Stan H.
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