# SOLUTION: please help me solve this division polynomial. I need to set up the equation and solve (2x^3-14x^2+19x+20)/(x-4)

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Question 88876: please help me solve this division polynomial. I need to set up the equation and solve
(2x^3-14x^2+19x+20)/(x-4)

Answer by jim_thompson5910(29613)   (Show Source):
You can put this solution on YOUR website!
Lets use synthetic division to divide

First lets find our test zero:

Set the denominator equal to zero
Solve for x.

so our test zero is 4

Now set up the synthetic division table by placing the test zero in the upper left corner and placing the coefficients of the numerator to the right of the test zero.
 4 | 2 -14 19 20 |

Start by bringing down the leading coefficient (it is the coefficient with the highest exponent which is 2)
 4 | 2 -14 19 20 | 2

Multiply 4 by 2 and place the product (which is 8) right underneath the second coefficient (which is -14)
 4 | 2 -14 19 20 | 8 2

Add 8 and -14 to get -6. Place the sum right underneath 8.
 4 | 2 -14 19 20 | 8 2 -6

Multiply 4 by -6 and place the product (which is -24) right underneath the third coefficient (which is 19)
 4 | 2 -14 19 20 | 8 -24 2 -6

Add -24 and 19 to get -5. Place the sum right underneath -24.
 4 | 2 -14 19 20 | 8 -24 2 -6 -5

Multiply 4 by -5 and place the product (which is -20) right underneath the fourth coefficient (which is 20)
 4 | 2 -14 19 20 | 8 -24 -20 2 -6 -5

Add -20 and 20 to get 0. Place the sum right underneath -20.
 4 | 2 -14 19 20 | 8 -24 -20 2 -6 -5 0

Since the last column adds to zero, we have a remainder of zero. This means is a factor of

Now lets look at the bottom row of coefficients:

The first 3 coefficients (2,-6,-5) form the quotient

So