SOLUTION: X^3 – 5x^2 + 2x + 20 divided by (x-3) gives a remainder of??
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Question 87917:  X^3 – 5x^2 + 2x + 20 divided by (x-3) gives a remainder of?? 
Answer by rapaljer(4671)   (Show Source): You can put this solution on YOUR website!
 You can do this the obvious way, by dividing the x-3 into the polynomial.  There are two ways to do this:  long division and synthetic division.
However, you can also do this by substitution.  
If P(x) = X^3 – 5x^2 + 2x + 20, then the remainder after division by x-3 is P(3).
P(3) = 3^3 -5*3^2 + 2*3 + 20 
P(3) = 27 - 45 + 6 + 20
P(3)= 8
The remainder is 8.  
You can also check this with a graphing calculator.  You can graph the function y1=X^3 – 5x^2 + 2x + 20, and evaluate the function at x = 3.  With a TI 83, 84, or 86, after you graph the function, you can look in the TABLE and look for x= 3.  Or you can just hit the TRACE button, and type the number 3.  The calculator gives the x and y value.  The y value is the answer to the problem. 
R^2  Retired from SCC 
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