SOLUTION: Please help me to solve the following problems: 76) 3/2y-3/2y+4 82) 4/3n+2/n+1+2/n^2+n

Question 87643: Please help me to solve the following problems:
76) 3/2y-3/2y+4

82) 4/3n+2/n+1+2/n^2+n

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
solve the following problems:
76) 3/2y-3/2y+4
3/(2y) - 3/(2y+4)
You need a lcd (least common denominator):
That would be 2y(2y+4)
Rewrite each fraction with that lcd as its denominator:
[3(2y+4)]/lcd - [3(2y)]/lcd
Combine the numerators to get:
= [12y+12]/lcd
Simplify:
= 12(y+1)/(2y)(2y+4)
= 12(y+1)/[4y(y+2)]
= 3(y+1)/y(y+2)
=================

82) 4/(3n) + 2/(n+1) + 2/(n^2+n)
lcd = 3n(n+1)
Rewrite:
= 4(n+1)/lcd + 2(3n)/lcd + 2(3)/lcd
= [4n+4+6n+6]/lcd
= [10(n+1)]/[3n(n+1)]
= 10/3n
==============
Cheers,
Stan H.

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