SOLUTION: Hello tutors! I'm stuck on this one. The answer is 4a^2/[9(a-1)], but I'm not sure how the 5 factors out. Thanks for any help you can give! 5a^2-20 ( a^3+2a^2 9a^3+6a^2)

SOLUTION: Hello tutors! I'm stuck on this one. The answer is 4a^2/[9(a-1)], but I'm not sure how the 5 factors out. Thanks for any help you can give! 5a^2-20 ( a^3+2a^2 9a^3+6a^2) _

Question 87264: Hello tutors! I'm stuck on this one. The answer is 4a^2/[9(a-1)], but I'm not sure how the 5 factors out. Thanks for any help you can give!
5a^2-20 ( a^3+2a^2 9a^3+6a^2)
_______ / ________ * __________
3a^2-12a (2a^2-8a 2a^2-4a)
Answer by longjonsilver(2297) (Show Source): You can put this solution on YOUR website!
You are looking for factorised versions that have same factors in so that we can cancel down and thus simplify.

i will do the numerator first:

And now the denominator --> has multiplications and divisions so it shouldn't matter which order we do them: I shall factorise everything first to see what i have.

what we have left now looks just as complicated but that is only because we have so many fractions in there.

Consider . This can be re-written as

so our can be thought of as

and finally we can start to simplify by cancelling out terms.

which is nowhere near what you say is the answer so i am guessing that my view of what you wrote is wrong... my method is fine - i have checked it a couple of times but admittedly it is difficult on here rather than on paper.

See if you follow what i did and apply it to your version of the question and see if you get the answer you quote.

Good luck
cheers
Jon.

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