SOLUTION: solve as quaditic equations 4x^2=13x+12

Question 87208: solve as quaditic equations
4x^2=13x+12
Found 2 solutions by Earlsdon, jim_thompson5910:
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
First, write the equation in standard form:
Solve by factoring.
Apply the zero products principle.
or
Therefore:

Or

Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

Get everything to one side

Now use the quadratic formula to solve for x:

Starting with the general quadratic

the general form of the quadratic equation is:

So lets solve

Plug in a=4, b=-13, and c=-12

Square -13 to get 169

Multiply to get

Combine like terms in the radicand (everything under the square root)

Simplify the square root

Multiply 2 and 4 to get 8

So now the expression breaks down into two parts

or

Lets look at the first part:

Add the terms in the numerator
Divide

So one answer is

Now lets look at the second part:

Subtract the terms in the numerator
Divide

So another answer is

So our solutions are:
or

Notice when we graph we get:

and we can see that the roots are and . This verifies our answer
RELATED QUESTIONS
Solve the following quadratic equations.... (answered by scott8148)
Solve... (answered by stanbon,Fombitz)
Solve... (answered by nabla)
Solve... (answered by rfer)
4x^2=13x+12 (answered by Stitch)
Solve the following quadratic equation. 4x^2 =13x + 12 (answered by checkley71)
Solve the following quadratic equation: 4x^2 = 13x + 12 (answered by funmath)
Solve the following quadratic equation. 4x^2 = 13x + 12 (answered by checkley75)
Solve the quadratic equation:... (answered by checkley75)