SOLUTION: i need help.. so far i have find the product of: 2[a^2+3(a-2)] and 3[a^2+3(a+1)] 2(a^2+3a-6) - then i distribute 2a^2+6a-12 3[a^2+3(a+1)] 3(a^2+3a-3)

SOLUTION: i need help.. so far i have find the product of: 2[a^2+3(a-2)] and 3[a^2+3(a+1)] 2(a^2+3a-6) - then i distribute 2a^2+6a-12 3[a^2+3(a+1)] 3(a^2+3a-3) - then i d

Question 865798: i need help.. so far i have
find the product of:
2[a^2+3(a-2)] and 3[a^2+3(a+1)]
2(a^2+3a-6) - then i distribute
2a^2+6a-12

3[a^2+3(a+1)]
3(a^2+3a-3) - then i distribute
3a^2+9a-9
how do i multiply -
2a^2+6a-12
3a^2+9a-9 ?
Found 2 solutions by mananth, josgarithmetic:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
2a^2+6a-12
3a^2+9a-9

put (a+3)=b
(2ab-12)(3ab-9)

Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Starting with:
More than one path to simplifying.

IF you want or must use Distributive property between the two trinomials, you can distribute from the right or from the left, but be consistant.

Simplify the terms inside the parentheses.

Cleanest general form including combining like-terms inside parentheses...

RELATED QUESTIONS
I need to express the following in the simplest form: {a^2+6a-7}... (answered by stanbon)
I need to factor and I do not understand this equation, please help... (answered by stanbon)
Please help solve. Find the Product of (3a^2)(-2ab). I came up with -6a^3b But... (answered by tutor_paul)
When I follow the example given in the text and factor and reduce the following I am not... (answered by Earlsdon,vleith)
How would I use the elimination method to solve this problem? 2a+b=3 -3a-2b=-1 This... (answered by MathLover1,MathTherapy)
Please help me solve this equation: {{{(3a-5)/(a^2+4a+3)+(2a+2)/(a+3)=(a-3)/(a+1)}}}... (answered by Greenfinch)
(6a^2-3a+9)/(a-2/3) (answered by josgarithmetic)
5/2a +1/6a... (answered by Maths68,IFY)
I need to find the quotient using long division. 9a^3-3a^2-3a+4 divided by 3a+2 I... (answered by richwmiller)