SOLUTION: factor completely -3t+3t^2-6t

Algebra.Com
Question 86478: factor completely
-3t+3t^2-6t

Answer by chitra(359)   (Show Source): You can put this solution on YOUR website!
The given expression is:



Here, we observe that there are two temrs which contain t and one term that contain . So grouping like terms, we get:



Here 3t can be taken out as the common factor. Hence, this cna be factored as:

3t(t - 3)

NOTE: If the given quadratic is equated top zero then the value of t can be found out in the way as shown below.

3t^2 - 9t = 0

==> 3t(t - 3) = 0

==> 3t = 0 OR t - 3 = 0

==> t = 0 OR t = 3


Hence, the solution..

Regards


RELATED QUESTIONS

factor completely... (answered by scott8148,jim_thompson5910)
Factor each polynomial. a^2-2a-35 Factor completely. -3t^3+ 3t^2-6t Factor... (answered by J2R2R)
6t+2+3t+17=10 (answered by rfer,Lisalsb)
Can anyone give me some help with this? I need the steps and solution: Factor... (answered by stanbon,Earlsdon)
46. Factor completely. -3t^3+ 3t^2-6t 60. Factor polynomial completely.... (answered by jim_thompson5910)
factoring this equation:... (answered by venugopalramana)
3t>6t+12 (answered by rfer)
6t+3<3t+12 (answered by josgarithmetic)
3t-7=5t then,... (answered by jim_thompson5910)