SOLUTION: Dividing Polynomials: synthetic 2x^4 - 10x^2 + 6x - 8 divided by x + 3 please help me if you can

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Question 85753: Dividing Polynomials: synthetic

2x^4 - 10x^2 + 6x - 8 divided by x + 3
please help me if you can

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!

Start with the given polynomial

First lets find our test zero:

Set the denominator equal to zero
Solve for x.

so our test zero is -3


Now set up the synthetic division table by placing the test zero in the upperleft corner and placing the coefficients of the numerator to the right of the test zero.(note: remember if a polynomial goes from to there is a zero coefficient. This is simply because really looks like
-3|20-106-8

Start by bringing down the leading coefficient (it is the coefficient with the highest exponent which is 2)
-3|20-106-8
2

Multiply -3 by 2 and place the product (which is -6) right underneath 0
-3|20-106-8
-6
2

Add -6 and 0 to get -6. Place the sum right underneath -6.
-3|20-106-8
-6
2-6

Multiply -3 by -6 and place the product (which is 18) right underneath -10
-3|20-106-8
-618
2-6

Add 18 and -10 to get 8. Place the sum right underneath 18.
-3|20-106-8
-618
2-68

Multiply -3 by 8 and place the product (which is -24) right underneath 6
-3|20-106-8
-618-24
2-68

Add -24 and 6 to get -18. Place the sum right underneath -24.
-3|20-106-8
-618-24
2-68-18

Multiply -3 by -18 and place the product (which is 54) right underneath -8
-3|20-106-8
-618-2454
2-68-18

Add 54 and -8 to get 46. Place the sum right underneath 54.
-3|20-106-8
-618-2454
2-68-1846

Since the last column adds to 46, we have a remainder of 46. This means is a not factor of
Now lets look at the bottom row of coefficients:

The first 4 coefficients (2,-6,8,-18) form the quotient



and the last coefficient 46, is the remainder, which is placed over like this


Putting this altogether, we get:



So

which looks like this in remainder form:
remainder 46

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