SOLUTION: Dividing Polynomials: synthetic
2x^4 - 10x^2 + 6x - 8 divided by x + 3
please help me if you can
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Question 85753: Dividing Polynomials: synthetic
2x^4 - 10x^2 + 6x - 8 divided by x + 3
please help me if you can
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given polynomial
First lets find our test zero:
Set the denominator equal to zero
Solve for x.
so our test zero is -3
Now set up the synthetic division table by placing the test zero in the upperleft corner and placing the coefficients of the numerator to the right of the test zero.(note: remember if a polynomial goes from to there is a zero coefficient. This is simply because really looks like
Start by bringing down the leading coefficient (it is the coefficient with the highest exponent which is 2)
Multiply -3 by 2 and place the product (which is -6) right underneath 0
Add -6 and 0 to get -6. Place the sum right underneath -6.
Multiply -3 by -6 and place the product (which is 18) right underneath -10
Add 18 and -10 to get 8. Place the sum right underneath 18.
Multiply -3 by 8 and place the product (which is -24) right underneath 6
Add -24 and 6 to get -18. Place the sum right underneath -24.
-3 | | | 2 | 0 | -10 | 6 | -8 |
| | | -6 | 18 | -24 | | |
| | 2 | -6 | 8 | -18 | |
Multiply -3 by -18 and place the product (which is 54) right underneath -8
-3 | | | 2 | 0 | -10 | 6 | -8 |
| | | -6 | 18 | -24 | 54 | |
| | 2 | -6 | 8 | -18 | |
Add 54 and -8 to get 46. Place the sum right underneath 54.
-3 | | | 2 | 0 | -10 | 6 | -8 |
| | | -6 | 18 | -24 | 54 | |
| | 2 | -6 | 8 | -18 | 46 |
Since the last column adds to 46, we have a remainder of 46. This means is a not factor of
Now lets look at the bottom row of coefficients:
The first 4 coefficients (2,-6,8,-18) form the quotient
and the last coefficient 46, is the remainder, which is placed over like this
Putting this altogether, we get:
So
which looks like this in remainder form:
remainder 46
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