SOLUTION: How do I do this, The product of two consecutive positive even integers is 120. Find the integers.

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Question 84897This question is from textbook algebra
: How do I do this,
The product of two consecutive positive even integers is 120. Find the integers. This question is from textbook algebra

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Let x=1st #, y=2nd #

Since we have 2 consecutive positive even integers, y=x+2. For instance, if our first number is 2, x=2. That means y=x+2=2+2=4. So we have
"The product of two consecutive positive even integers is 120"




Now use the quadratic formula to solve for x
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=484 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 10, -12. Here's your graph:


Since we're only looking for positive numbers, our first number is 10. So our second number is


So our two numbers are 10 and 12
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