SOLUTION: (a + b)^3 = a^3 + 3a^2b + 3ab^2+ b^3 for all values of a and b. Find an expression for the difference between the cubes of any two consecutive whole numbers.

Question 847481: (a + b)^3 = a^3 + 3a^2b + 3ab^2+ b^3 for all values of a and b.

Find an expression for the difference between the cubes of any two consecutive whole numbers.

Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

 

Hi,

(a + b)^3 = a^3 + 3a^2b + 3ab^2+ b^3 

(a +(- b))^3 = (a-b)^2 =  a^3 - 3a^2b + 3ab^2- b^3  

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