SOLUTION: Factor the polynomial completely. 9+8x-x^2 I've done it, but I know it's not right. Here's what I have: 9+8x+x^2 -x^2-x+9x+9 (-x^2+9)+ (-x+9) -x(x+9)+-1(x+9) (x+9)(-x-

Algebra.Com
Question 846667: Factor the polynomial completely.
9+8x-x^2
I've done it, but I know it's not right. Here's what I have:
9+8x+x^2
-x^2-x+9x+9
(-x^2+9)+ (-x+9)
-x(x+9)+-1(x+9)
(x+9)(-x-1)
Thank you for your help!

Answer by josh_jordan(263)   (Show Source): You can put this solution on YOUR website!
The easiest way to factor this is by first rewriting into standard form:

-x^2 + 8x + 9

Next, factor out the negative from the expression, which will make this even easier to factor:

-(x^2 - 8x - 9)

Now, we can easily factor the expression inside the parenthesis:

-(x - 9)(x + 1)

RELATED QUESTIONS

I have to completely factor this {{{ (x^2-9)^2 + 8x (x^2-9) }}} thank... (answered by jim_thompson5910)
Completely factor the following: x^4 - 13x^2 + 36 This what I have done, please let... (answered by wgomero)
I do not know what to do next, I have worked as far as I can but I do not now what to do... (answered by oscargut)
x^3-9x . . . How do I factor completely? I understand factoring cubes, but I don't know... (answered by checkley71)
I could really use some help answering the following question. I have tried to figure it (answered by stanbon)
factor:... (answered by nabla)
I have been told I need to turn my logs into exponents to solve this equation but I am... (answered by ewatrrr)
I am trying to figure out if the denominator of this fraction factors any lower than what (answered by solver91311)
log3(x+3)=2+log3(x-1) [3's are the bases] I have: log3(x+3)-log3(x-1)=2... (answered by josh_jordan)