It also appears to not be factorable.
The usual choices for checking integers would be 1 and 10; or 2 and 5. Any of those pair, regardless of sign choice, will NOT give the -1 and the -10 required.
Discriminant: .
Zeros at and .
The given quadratic trinomial is not factorable into two linear binomials; but if you really want, you can factor into binomials having the shown irrational constant terms. If you were looking for something simpler, then any simpler factorization is not possible.