SOLUTION: I need help to fully factor this problem: 3 * (2x-1)^2 * (2) * (x+3)^1/2 + (2x-1)^3 * (1/2) * (x+3)^-1/2 On the assumption that I started out correctly, I'm simply stuck with t

Question 84544This question is from textbook Precalculus, Mathematics for Calculus
: I need help to fully factor this problem:
3 * (2x-1)^2 * (2) * (x+3)^1/2 + (2x-1)^3 * (1/2) * (x+3)^-1/2
On the assumption that I started out correctly, I'm simply stuck with the expression as it is below:
(24x^2 - 24x + 6) * (x+3)^1/2 + (4x^3 - 6x^2 + 2x + x - 1/2) * (x+3)^-1/2
Any help at with this would be great! This question is from textbook Precalculus, Mathematics for Calculus

Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
I need help to fully factor this problem:
3 * (2x-1)^2 * (2) * (x+3)^1/2 + (2x-1)^3 * (1/2) * (x+3)^-1/2
You're expanding, not factoring. When you factor, you take out the lowest powers of what each term has in common:

That was a good one!!!
Happy Calculating!!!!
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