divide the fractions:
6p-18/9p divided by 3p-9/p^2+2p 
I really need somones help with this.

 divide the fractions:
 ÷ 

Invert the second fraction and change ÷ to ×

 ×  

Factor the two numerators and the bottom right
denominator:

 × 

Indicate the multiplication of the numerators
and denominators:

(6)(p-3)(p)(p+2)
  (9p)(3)(p-3)

Cancel the 3 in the bottom into the 6 in the top

 2
(6)(p-3)(p)(p+2)
  (9p)(3)(p-3)
       1

Cancel the (p-3)'s

 2   1
(6)(p-3)(p)(p+2)
  (9p)(3)(p-3)
       1   1

Cancel the p's

 2   1   1
(6)(p-3)(p)(p+2)
  (9p)(3)(p-3)
    1  1   1

All that left is

 2(p+2)
   9

which you can either leave in that
form or else distribute the 2 in the 
top like this:

  2p+4
    9

Edwin