SOLUTION: For 3x^3 �2x + 6 = 0, state the number of complex roots, the possible number of real roots, and the possible rational roots

Question 834605: For 3x^3 �2x + 6 = 0, state the number of complex roots, the possible number of real roots, and the possible rational roots
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
3 complex roots, due to the fundamental theorem of algebra.
The cubic must have at least one real root. It cannot have exactly two real roots, as the third would have non-zero imaginary part, which doesn't work (since the sum of the roots is real). So the cubic has either 1 or 3 real roots (in actuality, one).
Possible rational roots are of the form

where a divides 6 and b divides 3.
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