SOLUTION: Please help me solve the equation; x= -2, 0, 1 . It's supposed to be a polynomial function in standard form with given zeros. So far I've tried: x= -2, 0, 1 f(x)= (x+2) (x-0) (x-

Question 830155: Please help me solve the equation; x= -2, 0, 1 . It's supposed to be a polynomial function in standard form with given zeros. So far I've tried:
x= -2, 0, 1
f(x)= (x+2) (x-0) (x-1)
f(x)= (x+2) (x^2-1x) ?
From there I didn't understand the rest.
Thank you!
Found 2 solutions by Alan3354, TimothyLamb:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Please help me solve the equation; x= -2, 0, 1 . It's supposed to be a polynomial function in standard form with given zeros. So far I've tried:
x= -2, 0, 1
f(x)= (x+2) (x-0) (x-1)
f(x)= (x+2) (x^2-1x)
--------------
What you did is right.
Just multiply the rest.
f(x)= (x+2) (x^2 - x)

Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
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given zeroes: x = -2, 0, 1
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(x + 2)(x - 0)(x - 1) = 0
(x + 2)(x)(x - 1) = 0
x(x + 2)(x - 1) = 0
x(xx - 1x + 2x - 2) = 0
x(xx + x - 2) = 0
xxx + xx - 2x = 0
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answer:
x^3 + x^2 - 2x = 0
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