SOLUTION: Three consecutive evenintegers are such that the square of the third is 76 more than the square of the seconf. Find the three integers. Evaluate this function for x=32(32-bit

Question 82755: Three consecutive evenintegers are such that the square of the third is 76 more than the square of the seconf. Find the three integers.

Evaluate this function for x=32(32-bit true color)

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers.
:
Let x = 2nd consecutive number
Then (x+2) = 3rd consecutive number
:
"the third is 76 more than the square of the second." which can be written:
(x+2)^2 = 76 + x^2
:
x^2 + 4x + 4 = x^2 + 76
:
x^2 - x^2 + 4x = 76 - 4
:
4x = 72
:
x = 72/4
:
x = 18 is the 2nd even consecutive number
:
16, 18, 20 are the numbers
:
Check on a calc: 20^2 - 18^2 = 76

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