SOLUTION: three brothers have ages that are consecutive multiples of five, the sum of their ages two years ago was 69. what are their ages now?
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Question 827450: three brothers have ages that are consecutive multiples of five, the sum of their ages two years ago was 69. what are their ages now?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
three brothers have ages that are consecutive multiples of five, the sum of their ages two years ago was 69. what are their ages now?
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1st: 5x-5
2nd: 5x
3rd: 5x+5
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Equation:
5x-7 + 5x-2 + 5x+3 = 69
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15x - 6 = 69
15x = 75
x = 5
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1st: 5x-5 = 25-5 = 20 yrs
2nd: 25 yrs
3rd: 30 yrs
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Cheers,
Stan H.
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