SOLUTION: I need help factoring this question, The x roots on a parabola are 6 and -4 and the parabola cuts the Y axes at -1. Put this in the form of Y=a(x-s)(x-t)

Question 824356: I need help factoring this question,
The x roots on a parabola are 6 and -4 and the parabola cuts the Y axes at -1. Put this in the form of Y=a(x-s)(x-t)
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
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given:
y-intercept: -1
roots: 6 and -4
--
standard form:
f(x) = ax^2 + bx + c
--
y-intercept: -1
f(0) = -1 = a(0)^2 + b(0) + c
-1 = 0 + 0 + c
c = -1
---
roots: 6 and -4
(x - 6)(x + 4) = 0
x^2 + 4x - 6x - 24 = 0
x^2 - 2x - 24 = 0
note: c = -24
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make c = -1
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x^2 - 2x - 24 = 0
(x^2 - 2x - 24)(1/24) = 0
(1/24)x^2 - (2/24)x - 24/24 = 0
(1/24)x^2 - (1/12)x - 1 = 0
---
(x^2 - 2x - 24)(1/24) = 0
put into factored form:
answer:
y(x) = (x - 6)(x + 4)(1/24)
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graph:
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