SOLUTION: Find three consecutive odd numbers where the product of the smaller numbers is 22 less than the square of the last number. (this is what i did) {{{n+(n+2)=(n+4)^2-22}}} {{{2n+

Question 818325: Find three consecutive odd numbers where the product of the smaller numbers is 22 less than the square of the last number.
(this is what i did)

now i don't know how to take the exponent out..
the lesson I had, had two exponents cancelling each other like this.

Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
You added the left side instead of multiplying
should be

n^2+2n=n^2+8n-6
6=6n
1=n

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