SOLUTION: how to factor: 2y^+8y+6

Question 816940: how to factor:
2y^+8y+6
Found 2 solutions by stanbon, doodles:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
how to factor:
2y^+8y+6
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= 2(y^2 + 4y + 3)
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= 2(y^2+3y+y+3)
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= 2(y(y+3) + (y+3))
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= 2(y+3)(y+1)
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Cheers,
Stan H.
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Answer by doodles(24) (Show Source): You can put this solution on YOUR website!
I assuming 2y^2+8y+6
Since there is no real obvious factor we can use we should factor any common denominators in this equation (which is 2). So the equation is easier to work with.

Accordingly, we have to factor out which will be:

So in truth the facros we have are:

or you could write it as:

and to check:
F:
O:
I:
L:
Which leaves us with our original equation:
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