SOLUTION: Solve the system
y = x^2 - 4x - 15
y = 2x - 1
Algebra.Com
Question 815645: Solve the system
y = x^2 - 4x - 15
y = 2x - 1
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Solve the system
y = x^2 - 4x - 15
y = 2x - 1
y = y therefore
2x - 1 = x^2 - 4x - 15
0 = x^2 - 4x - 2x - 15 + 1
A quadratic equation, solve for x:
x^2 - 6x - 14 = 0
We have to use the quadratic formula to find x
Two solutions,
x = -1.796
x = 7.796
:
I'll let you find y for both solutions
RELATED QUESTIONS
Solve the system :
y = x^2 + 1
y = 4x + 1
(answered by checkley71)
solve the following system of equations algebraically. {{{ y=x^2+4x-2 and y=2x+1... (answered by Love math)
Solve this system of equations:
y=x^2-2x-1
y=-x^2+4x-1
(answered by farbonara)
Use the method of substitution to solve the system of linear equations
a) x-y=8... (answered by MathLover1)
solve this linear system using the method of substitution:
1/4x + 1/2y = -5/12
2x -... (answered by josgarithmetic,macston)
Solve the system by graphing, substitution, or elimination.
1. Y=2
Y=x^2-14
2.... (answered by Alan3354)
solve the system of equations:
y=x^2-4x+3... (answered by jorel1380)
by using quadratic system of equations solve each system by substitution.
{y=2x^2-5x+3
(answered by ewatrrr)
solve the following system of equations algebraically
a. y=2x^2+20x+15 and y=7x
b.... (answered by Alan3354)