SOLUTION: Find the excluded value(s) for the following expression : 4x ----- x^2+x-6

Question 812604: Find the excluded value(s) for the following expression :
4x
-----
x^2+x-6
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!
First, please don't try to use horizontal fraction bars on algebra.com. They rarely come out looking good and they are often hard to tell what it really is. Instead, put the numerator and denominator in parentheses and use a slash. For example, your fraction would be (4x)/(x^2+x-6).

In your problem the "excluded values" would be those that would make the denominator zero (since division by zero is undefined). So we find them by setting the denominator to zero and solving:

To solve we start by factoring:

Then the Zero Product Property:
x+3 = 0 or x-2 = 0
Solving these we get:
x = -3 or x = 2
These are the "excluded values".
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