SOLUTION: I am doing a factoring problem: 36k^2- 48k+18 and got 4(3k-2)^2 but i am not sure if its right can you tell me if i got it right. if not right then please demonstrate how to do it

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Question 804751: I am doing a factoring problem: 36k^2- 48k+18 and got 4(3k-2)^2 but i am not sure if its right can you tell me if i got it right. if not right then please demonstrate how to do it
Found 3 solutions by richwmiller, solver91311, Edwin McCravy:
Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
36k^2- 48k+18
factor 6
6*(6k^2-8k+3)
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!




has no real number factors. You can tell because 4(36)(18) is larger than -48 squared.

If the problem had been



Then your answer would have been correct.

John

Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
The Out Campaign: Scarlet Letter of Atheism
Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!
36k²-48k+18

All you can do with that is factor out 6

6(6k²-8k+3)

The quadratic in the parentheses will not factor further.

So I think you made a typo with the 18 and meant 16.

36k²-48k+16 
4(9k²-12k+4)
4(3k-2)(3k-2)
4(3k-2)²

If the 18 should have been 16 then your answer is correct.

Edwin
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