SOLUTION: I'm attempting to help a friend earning her BSN with an equation. I have not done this level of math in many years and I honestly don't know where to begin. The question is : (

Question 803013: I'm attempting to help a friend earning her BSN with an equation. I have not done this level of math in many years and I honestly don't know where to begin.
The question is : (3x^3-5x^2-32x+7)/x-4=
If you would please explain and "show your work" as to how you arrive at your answer it would be greatly appreciated.
Thanks in advance.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
(3x^3-5x^2-32x+7)/(x-4)
-----
That is a long-division problem, unless your friend
knows something about synthetic division::
----
4)....3....-5....-32....7
...........12....28....-16
......3.....7....-4...|..-9
===========
Quotient:: 3x^2 + 7x -4
Remainder: -9
=================
Cheers,
Stan H.
=================

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