SOLUTION: Please help me with this mixture problem. I have no idea how to do it. THanks A car radiator contains 10 liters of a 30% antifreeze solution. how many liters will have to be repla

Question 7860: Please help me with this mixture problem. I have no idea how to do it. THanks
A car radiator contains 10 liters of a 30% antifreeze solution. how many liters will have to be replaced with pure antifreeze if the resulting solution is to be 50% antifreeze?
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Let x = the number of liters of antifreeze that must be replaced. Change percentages to decimals.
Start with 10 liters of 30% antifreeze. Write this as: 0.3(10)
You want to remove x liters of 30% antifreeze. Write this as -0.3(x)
Then you want add x liters of 100% antifreeze. Write this as +1(x) or just +x.
Now all of this must add up to 10 liters of 50% antifreeze. Write this as 0.5(10).
Putting it all together, we have:
Simplify and solve for x.

You must remove 2.86 liters of 30% antifreeze then add 2.86 liters of 100% antifreeze.

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