SOLUTION: Solve =
2x2(square) + 3 = 7x
Algebra.Com
Question 77656: Solve =
2x2(square) + 3 = 7x
Found 2 solutions by tutorcecilia, praseenakos@yahoo.com:
Answer by tutorcecilia(2152) (Show Source): You can put this solution on YOUR website!
=
= [Isolate all of the terms to one side and set the equation equal to zero]
.
= [factor]
(2x-1=0 [set each factor equal to zero and solve for x]
2x-1=0
2x=1
x=1/2
.
(x-3)=0
x-3=0
x=3
.
Check by plugging either value of x back into the original equation and solve.
Answer by praseenakos@yahoo.com(507) (Show Source): You can put this solution on YOUR website!
Question:
2x^2 + 3 = 7x
Answer:
2x^2 + 3 = 7x
2x^2 + 3 - 7x = 7x - 7x , subtract 7x from both sides.
==> 2x^2 - 7x + 3 = 0
Now split the middle term, that is -7x.
For that find two numbers whose sum is -7(that is coefficient of x ) and their product is 6 (that is 2* 3 )
Such two numbers are -6 and -1
==> 2x^2 -6x - 1x + 3 = 0
Now group the terms
==> 2x ( x - 3 ) - ( x-3) = 0
==> (x - 3 )( 2x - 1) = 0
==> Either (x - 3 ) = 0 or (2x - 1 ) = 0
==> x = 3 or 2x = 1
==> x = 3 or x = 1/2
These are the solutions of the given polinomial.
Hope you understood.
Regards.
Praseena.
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