In order to factor , first we need to ask ourselves: What two numbers multiply to -15 and add to 2? Lets find out by listing all of the possible factors of -15
Factors:
1,3,5,15,
-1,-3,-5,-15,List the negative factors as well. This will allow us to find all possible combinations
These factors pair up to multiply to -15.
(-1)*(15)=-15
(-3)*(5)=-15
Now which of these pairs add to 2? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 2
| First Number | | | Second Number | | | Sum | | 1 | | | -15 | || | 1+(-15)=-14 | | 3 | | | -5 | || | 3+(-5)=-2 | | -1 | | | 15 | || | (-1)+15=14 | | -3 | | | 5 | || | (-3)+5=2 | We can see from the table that -3 and 5 add to 2.So the two numbers that multiply to -15 and add to 2 are: -3 and 5
Now we substitute these numbers into a and b of the general equation of a product of linear factors which is:
substitute a=-3 and b=5
So the equation becomes:
(x-3)(x+5)
Notice that if we foil (x-3)(x+5) we get the quadratic again
Factor the bottom numerator
| Solved by pluggable solver: Factoring Quadratics with a leading coefficient of 1 (a=1) |
In order to factor , first we need to ask ourselves: What two numbers multiply to -25 and add to 0? Lets find out by listing all of the possible factors of -25
Factors:
1,5,25,15,
-1,-5,-25,-15,List the negative factors as well. This will allow us to find all possible combinations
These factors pair up to multiply to -25.
(-1)*(15)=-25
(-5)*(25)=-25
Now which of these pairs add to 0? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 0
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