SOLUTION: Please help!! Differentiate the following function with respect to t. y = 5/t^2 + 6t^3 - sqrt t Thanks!!

Algebra.Com
Question 77142: Please help!!
Differentiate the following function with respect to t.
y = 5/t^2 + 6t^3 - sqrt t
Thanks!!

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Differentiate the following function with respect to t.
y = 5/t^2 + 6t^3 - sqrt t
Rewrite as:
y = 5t^-2 + 6t^3 - t^(1/2)
y' = -10t^-3 + 18t^2 - (1/2)t^(-1/2)
---------------
Cheers,
Stan H.

RELATED QUESTIONS

Differentiate the following functions with respect to t: i) y = 2t^2. Cos(t) ii) y... (answered by Edwin McCravy)
What is the rate of change of f(t)=(6t-5)(t+7) with respect to t when t=7 ? Thanks! I (answered by John10)
What is the rate of change of f(t)=(6t-5)(t+7) with respect to t when t=7 ? Thanks! I am (answered by richard1234)
Good evening! I'm having trouble finding the zeros for f(t) = t^5 -6t^3 + 9t I... (answered by Edwin McCravy)
can you please help me with 5=-1(2+6t)-t i got up to 5=-2-6t-t i just dont understand... (answered by Finavon)
differentiate v(0)coswt with respect to... (answered by Alan3354)
What is the rate of change of f(t)=(6t-5)(t+7) with respect to t when t=7 ? Supposedly,... (answered by Alan3354)
Please help. I have two questions. 1. Identify the function represented by y=3/x 2.... (answered by Alan3354)
Please help me with this algebra question. Thank you very much... (answered by checkley71)