SOLUTION: Do you know what the horizontal asymptote of this problem is? f(x)=(x^2+4x-5)/(x+1)

Question 770860: Do you know what the horizontal asymptote of this problem is?
f(x)=(x^2+4x-5)/(x+1)
Found 2 solutions by solver91311, tommyt3rd:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

Yes. There is no horizontal asymptote. If the degree of the numerator polynomial is larger than the degree of the denominator polynomial, then there is an oblique asymptote that has an equation equal to the quotient of the numerator divided by the denominator using polynomial long division (excluding any remainder)

John

Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it

Answer by tommyt3rd(5050) (Show Source): You can put this solution on YOUR website!
since the degree of the numerator is greater than the degree of the numerator, this function has no horizontal asymptotes
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