SOLUTION: I am having troubling factoring 3z^2+13z+14
I have tried
(3z-1)(z-14)
(3z+1)(3z+14) and I can't get the right answer!
Algebra.Com
Question 769523: I am having troubling factoring 3z^2+13z+14
I have tried
(3z-1)(z-14)
(3z+1)(3z+14) and I can't get the right answer!
Found 2 solutions by Alan3354, Kat1315:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
I am having troubling factoring 3z^2+13z+14
I have tried
(3z-1)(z-14)
(3z+1)(3z+14) and I can't get the right answer!
-------------
3z^2+13z+14 has no negative, so all terms are +
----
(3z+1)(3z+14) won't work, it gives 9z^2
-----------
Both of your attempts used 1*14 for 14
Try using 14 = 2*7
Answer by Kat1315(1) (Show Source): You can put this solution on YOUR website!
The answer is (3z+7) (z+2)
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