Solved by pluggable solver: Factoring Quadratics with a leading coefficient of 1 (a=1) | |||||||||||||||||||||||||
In order to factor Factors: 1,2,3,6, -1,-2,-3,-6,List the negative factors as well. This will allow us to find all possible combinations These factors pair up to multiply to 6. 1*6=6 2*3=6 (-1)*(-6)=6 (-2)*(-3)=6 note: remember two negative numbers multiplied together make a positive number Now which of these pairs add to -7? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -7
So in other words, factor the polynomials. x^2+... (answered by drj) Factor each of the following polynomials: 14x^2 - 20x + 6 My answer for this... (answered by checkley75) Factor:... (answered by jim_thompson5910) factor... (answered by Mathtut) Factor the following polynomials: 1. 3+x^2-13x 2. x^2+5-7x 3. 9-17y+8y^2 4. 4T^2-7-3T (answered by ) factor the following polynomials as completely as possible... (answered by stanbon) x^2-7x-4/x-2 whats the... (answered by rothauserc) x^2-7x-4/x-2 whats the... (answered by Fombitz) Factor each of the following polynomials completly 14x^2 - 20x +... (answered by prabhjyot) |