SOLUTION: Choose the real solutions of the system: x = (y^2) + -9 and x - 4y - 12 = 0 I tried using the substitution method but I keep getting stuck!

Question 757031: Choose the real solutions of the system:
x = (y^2) + -9 and x - 4y - 12 = 0
I tried using the substitution method but I keep getting stuck!
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
x = (y^2) + -9 and x - 4y - 12 = 0
from second equation. Substitute into the first equation.

You should no longer be stuck. The lefthand side is factorable.

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Just a little bit of review:

If you find some square trinomial as any general and you want to factor it, try thinking of it as
So you are looking for two numbers, h and k, so that hk=b and h+k=a.
What you do is look for all the two-number factorizations for b, and find which ones give you a sum of a. We then test each combination until we find something that works. There is a somewhat more analytical way also, but the search and test method is usually enough.
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