SOLUTION: (r+4)^4 I need help solving this one. Thank you

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Question 75663: (r+4)^4 I need help solving this one.
Thank you

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
You could write this as
%28r%2B4%29%28r%2B4%29%28r%2B4%29%28r%2B4%29 and multiply this out the long way, but there is a much faster way to tackle these sort of problems. We're going to use Binomial Expansion to expand this term. The general rule to expand %28a%2Bb%29%5En is that we start out with c%2Aa%5En%2Ab%5E0 and for each term we decrement n for a and increment the exponent for b so the 2nd terms looks like c%2Aa%5E%28n-1%29b%5E1 until we get to c%2Aa%5E0b%5En for our last term. The coefficient (c) that is placed in front of each term is found in Pascal's triangle. So for %28a%2Bb%29%5E4 we need to look at the row containing:
1,4,6,4,1
And these coefficients are placed in front of the variables. So if we have
%28r%2B4%29%5E4 it becomes
Notice the terms in the parenthesis are the coefficients
r%5E4%2B4%2A4r%5E3%2B6%2A16r%5E2%2B4%2A64r%2B256
r%5E4%2B16r%5E3%2B96r%5E2%2B256r%2B256
Hope this makes sense. If not just look at row containing
1,2,1
This is the row of coefficients that are appended to the expansion of
%28a%2Bb%29%5E2
which expands to:
a%5E2%2B2ab%2Bb%5E2
which can be written as:
%281%29a%5E2%2Ab%5E0%2B%282%29a%5E1b%5E1%2B%281%29a%5E0b%5E2
and you can see the coefficients from the triangle in the parenthesis.