SOLUTION: If x+a is a factor of the polynomial x^2 + px + q and x^2 + mx + n, then prove that a = (n-q) / (m-p).
Algebra.Com
Question 756502: If x+a is a factor of the polynomial x^2 + px + q and x^2 + mx + n, then prove that a = (n-q) / (m-p).
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
If is a factor in
and in
, then
and
.
That would give as a system of equations that looks confusing, but we only need to solve it partially.
--> --> --> --> --> --> -->
RELATED QUESTIONS
If x+a is a factor of the polynomial x2+px+q, x2+mx+n. Prove that a=... (answered by richard1234)
If the solution for x of x^2+px+q=0 are the cubes of the solutions for x^2+mx+n=0,... (answered by ikleyn)
All the roots of
x^2 + px + q = 0 are real, where p and q are real numbers. Prove that... (answered by ikleyn)
If (x-2)^2 is a factor of x^3+px+q, find the value of p and q. Please help.. (answered by KMST)
If x+4-4i is a factor of the function f(x) = px^2 + qx + r, show that p,q and r are in... (answered by josgarithmetic)
For this problem: All the roots of
x^2 + px + q = 0 are real, where p and q are real... (answered by Edwin McCravy,AnlytcPhil,Plocharczyk,mccravyedwin)
If the polynomial function
P(x) = an^x^n + an−1^x^n−1 + ... + a1^x + a0
has integer (answered by ikleyn)
For this problem: All the roots of
x^2 + px + q = 0 are real, where p and q are real... (answered by Edwin McCravy)
So for this question(All the roots of
x^2 + px + q = 0 are real, where p and q are real... (answered by ikleyn)