SOLUTION: FIND THE VALUE FOR b SUCH THAT THE TRINOMIAL IS A SQUARE x^2+bx+25

Question 756298: FIND THE VALUE FOR b SUCH THAT THE TRINOMIAL IS A SQUARE
x^2+bx+25
Answer by algebraic penguin(13) (Show Source): You can put this solution on YOUR website!
hello,
Since the trinomial is a square, then the trinomial could be represented in the form (x+a)^2=x^2+2ax+a^2.
Since we are given that the resulting trinomial is x^2+bx+25, we know that a^2=25, so a=5 or -5.
Hence, the possible functions are x^2+2(5)+25 or x^2+2(-5)+25. Thus b=2(5) or 2(-5).
The possible values of b are 10 and -10.
Thanks for choosing algebra.com!
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