SOLUTION: can someone check tese for me please?
divide
40x^3-48X^2
over
8x
=5x-6x
and
x^3+2x^2+x+12x+3
=x^2+x-4
Algebra.Com
Question 75573: can someone check tese for me please?
divide
40x^3-48X^2
over
8x
=5x-6x
and
x^3+2x^2+x+12x+3
=x^2+x-4
Answer by 303795(602) (Show Source): You can put this solution on YOUR website!
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