SOLUTION: Solve for x: {(3^x9^x+20)/(27^2x+5)}=81^x+5

Question 74477: Solve for x: {(3^x9^x+20)/(27^2x+5)}=81^x+5
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
I have added parentheses to the equation which I think were missing:
(3^x*9^(x+20))/(27^(2x+5))=81^(x+5)

Reduce all the numbers in the unknown terms to powers of 3 and simplify
or

Multiply both sides by the denominator on the left side

Since bases are the same, exponents are equal
so
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