SOLUTION: this was on my test, I need to correct it, but I can't figure it out:
Simplify the following complex fraction.
2 3
---- - ----
x-3 x+3
___________
5 4
--
Algebra.Com
Question 74460: this was on my test, I need to correct it, but I can't figure it out:
Simplify the following complex fraction.
2 3
---- - ----
x-3 x+3
____________
5 4
--- - ----
x^2-9 x-3
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
the numerator is:
[(2(x+3)-3(x-3)]/(x-3)(x+3)
(2x+6-3x+9)/(x-3)(x+3)
(-x+15)/(x-3)(x+3)
now the denominator
[5(x-3)-4(x^2-9)]/(x^2-9)(x-3)
(5x-15-4x^2+36)/(x-3)(x+3)(x-3)
(-4x^2+5x+21)/(x-3)(x+3)(x-3)
(-x+3)(4x+7)/(x-3)(x+3)(x-3)
-----------------------------------------
now we invert the denominator & multiply
(-x+15)/(x-3)(x+3)*(x-3)(x+3)(x-3)/(-x+3)(4x+7) now we cancel out all common terms in the numerator & the denominator:
(-x+15)(x-3)/(-x+3)(4x+7)
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