SOLUTION: can you check my answer? 7x^2+6x from 9x^2-3 9x^2-3 7x^2-6 =2x^2-3 9x^2-3 7x^2+6 =2x^--3

Question 74278: can you check my answer?
7x^2+6x from 9x^2-3
9x^2-3
7x^2-6
=2x^2-3
9x^2-3
7x^2+6
=2x^--3

Found 2 solutions by Cintchr, stanbon:
Answer by Cintchr(481) (Show Source): You can put this solution on YOUR website!
If you are subtracting, a major error can occur. WATCH YOUR SIGNS!!!

In your problem you forgot the 'x' with the 6.
Distribute the negative

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
can you check my answer?
7x^2+6x from 9x^2-3
9x^2-3
7x^2-6
----------------
=2x^2+3
You subtracted 7 from 9 and got 2 correctly.
You should subtract -6 from -3 and get +3
The Rule is : "change the sign of the -6 to +6 and then add" to get +3
---------
Cheers,
Stan H.

RELATED QUESTIONS
multiply... (answered by fractalier)
find the product -9x(-6x^3-7x^2+2x+8) (answered by ReadingBoosters)
combine like terms in each please.. 8x^2+6x^3+2x+5x... (answered by fractalier)
7x^2+6x - 9x^2-3 My answer is -2*x^2+6*x-3. Is this correct? (answered by stanbon)
add... (answered by algebrahouse.com)
Simplify:(5x^2-2x+1)-(9x^2-7x-3) (answered by user_dude2008)
Solve: 7x\6-2=9x\6-3... (answered by elima)
(9x^4+2x^3-x+5)+(9x^3-3x^2+8x+3)-(7x^4-x+12) (answered by CubeyThePenguin)
9x^3-7x^2+441x-343=0 (answered by ikleyn)